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8(x-1)+3=2(x-4)+1
We move all terms to the left:
8(x-1)+3-(2(x-4)+1)=0
We multiply parentheses
8x-(2(x-4)+1)-8+3=0
We calculate terms in parentheses: -(2(x-4)+1), so:We add all the numbers together, and all the variables
2(x-4)+1
We multiply parentheses
2x-8+1
We add all the numbers together, and all the variables
2x-7
Back to the equation:
-(2x-7)
8x-(2x-7)-5=0
We get rid of parentheses
8x-2x+7-5=0
We add all the numbers together, and all the variables
6x+2=0
We move all terms containing x to the left, all other terms to the right
6x=-2
x=-2/6
x=-1/3
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