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-2x^2+9x-3=0
a = -2; b = 9; c = -3;
Δ = b2-4ac
Δ = 92-4·(-2)·(-3)
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{57}}{2*-2}=\frac{-9-\sqrt{57}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{57}}{2*-2}=\frac{-9+\sqrt{57}}{-4} $
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