5(2x-7)+x=4(3x+1)-48

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Solution for 5(2x-7)+x=4(3x+1)-48 equation: 



5(2x-7)+x=4(3x+1)-48

We move all terms to the left:

5(2x-7)+x-(4(3x+1)-48)=0

We add all the numbers together, and all the variables

x+5(2x-7)-(4(3x+1)-48)=0

We multiply parentheses

x+10x-(4(3x+1)-48)-35=0



We calculate terms in parentheses: -(4(3x+1)-48), so:

4(3x+1)-48

We multiply parentheses

12x+4-48

We add all the numbers together, and all the variables

12x-44

Back to the equation:

-(12x-44)



We add all the numbers together, and all the variables

11x-(12x-44)-35=0

We get rid of parentheses

11x-12x+44-35=0

We add all the numbers together, and all the variables

-1x+9=0

We move all terms containing x to the left, all other terms to the right

-x=-9

x=-9/-1

x=+9

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