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3(3x+5)+13=2(8x-9)+60
We move all terms to the left:
3(3x+5)+13-(2(8x-9)+60)=0
We multiply parentheses
9x-(2(8x-9)+60)+15+13=0
We calculate terms in parentheses: -(2(8x-9)+60), so:We add all the numbers together, and all the variables
2(8x-9)+60
We multiply parentheses
16x-18+60
We add all the numbers together, and all the variables
16x+42
Back to the equation:
-(16x+42)
9x-(16x+42)+28=0
We get rid of parentheses
9x-16x-42+28=0
We add all the numbers together, and all the variables
-7x-14=0
We move all terms containing x to the left, all other terms to the right
-7x=14
x=14/-7
x=-2
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