1/3(6x-12)-2x+5=4(2x-1))

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Solution for 1/3(6x-12)-2x+5=4(2x-1)) equation: 



1/3(6x-12)-2x+5=4(2x-1))

We move all terms to the left:

1/3(6x-12)-2x+5-(4(2x-1)))=0



Domain of the equation: 3(6x-12)!=0

x∈R



We add all the numbers together, and all the variables

-2x+1/3(6x-12)-(4(2x-1)))+5=0

We multiply all the terms by the denominator


-2x*3(6x-12)-((4(2x-1)))+5)*3(6x+1-12)=0



We calculate terms in parentheses: -((4(2x-1))), so:

(4(2x-1))



We calculate terms in parentheses: +(4(2x-1)), so:

4(2x-1)

We multiply parentheses

8x-4

Back to the equation:

+(8x-4)



We get rid of parentheses

8x-4

Back to the equation:

-(8x-4)



We add all the numbers together, and all the variables

-2x*3(6x-12)-(8x-4)+5)*3(6x-11)=0

We add all the numbers together, and all the variables

-2x*3(6x-12)-(8x-4)+5)*3(6x=0

Wy multiply elements

-6x^2(6-(8x-4)+5)*3(6x=0

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