8(r-5)-7(r-1)=2(r+4)

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Solution for 8(r-5)-7(r-1)=2(r+4) equation: 



8(r-5)-7(r-1)=2(r+4)

We move all terms to the left:

8(r-5)-7(r-1)-(2(r+4))=0

We multiply parentheses

8r-7r-(2(r+4))-40+7=0



We calculate terms in parentheses: -(2(r+4)), so:

2(r+4)

We multiply parentheses

2r+8

Back to the equation:

-(2r+8)



We add all the numbers together, and all the variables

r-(2r+8)-33=0

We get rid of parentheses

r-2r-8-33=0

We add all the numbers together, and all the variables

-1r-41=0

We move all terms containing r to the left, all other terms to the right

-r=41

r=41/-1

r=-41

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