6(x-2)+1=2(3x-5)+9

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Solution for 6(x-2)+1=2(3x-5)+9 equation: 



6(x-2)+1=2(3x-5)+9

We move all terms to the left:

6(x-2)+1-(2(3x-5)+9)=0

We multiply parentheses

6x-(2(3x-5)+9)-12+1=0



We calculate terms in parentheses: -(2(3x-5)+9), so:

2(3x-5)+9

We multiply parentheses

6x-10+9

We add all the numbers together, and all the variables

6x-1

Back to the equation:

-(6x-1)



We add all the numbers together, and all the variables

6x-(6x-1)-11=0

We get rid of parentheses

6x-6x+1-11=0

We add all the numbers together, and all the variables

-10!=0

There is no solution for this equation

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