7x-3(x-4)=-8+8(x-4)

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Solution for 7x-3(x-4)=-8+8(x-4) equation: 



7x-3(x-4)=-8+8(x-4)

We move all terms to the left:

7x-3(x-4)-(-8+8(x-4))=0

We multiply parentheses

7x-3x-(-8+8(x-4))+12=0



We calculate terms in parentheses: -(-8+8(x-4)), so:

-8+8(x-4)

determiningTheFunctionDomain
8(x-4)-8

We multiply parentheses

8x-32-8

We add all the numbers together, and all the variables

8x-40

Back to the equation:

-(8x-40)



We add all the numbers together, and all the variables

4x-(8x-40)+12=0

We get rid of parentheses

4x-8x+40+12=0

We add all the numbers together, and all the variables

-4x+52=0

We move all terms containing x to the left, all other terms to the right

-4x=-52

x=-52/-4

x=+13

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