.4(2-3x)=2(.3x+.4)-3.6

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Solution for .4(2-3x)=2(.3x+.4)-3.6 equation: 



.4(2-3x)=2(.3x+.4)-3.6

We move all terms to the left:

.4(2-3x)-(2(.3x+.4)-3.6)=0

We add all the numbers together, and all the variables

.4(-3x+2)-(2(.3x+0.4)-3.6)=0

We multiply parentheses

-1.2x-(2(.3x+0.4)-3.6)+0.8=0



We calculate terms in parentheses: -(2(.3x+0.4)-3.6), so:

2(.3x+0.4)-3.6

We multiply parentheses

2x+0.8-3.6

We add all the numbers together, and all the variables

2x-2.8

Back to the equation:

-(2x-2.8)



We get rid of parentheses

-1.2x-2x+2.8+0.8=0

We add all the numbers together, and all the variables

-3.2x+3.6=0

We move all terms containing x to the left, all other terms to the right

-3.2x=-3.6

x=-3.6/-3.2

x=1+0.4/3.2

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