2/3y+1=1/6y+

Solution for 2/3y+1=1/6y+ equation:

2/3y+1=1/6y+

We move all terms to the left:

2/3y+1-(1/6y+)=0


Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



Domain of the equation: 6y+)!=0

y∈R


We add all the numbers together, and all the variables

2/3y-(+1/6y)+1=0

We get rid of parentheses

2/3y-1/6y+1=0

We calculate fractions


12y/18y^2+(-3y)/18y^2+1=0

We multiply all the terms by the denominator


12y+(-3y)+1*18y^2=0

Wy multiply elements

18y^2+12y+(-3y)=0

We get rid of parentheses

18y^2+12y-3y=0

We add all the numbers together, and all the variables

18y^2+9y=0

a = 18; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·18·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*18}=\frac{-18}{36}
=-1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*18}=\frac{0}{36}
=0
$