7-0.75x=7(3/28x+1)

Solution for 7-0.75x=7(3/28x+1) equation:

7-0.75x=7(3/28x+1)

We move all terms to the left:

7-0.75x-(7(3/28x+1))=0


Domain of the equation: 28x+1))!=0

x∈R


We multiply all the terms by the denominator


-(0.75x)*28x+7*28x+1))-(7(3+1))=0

We add all the numbers together, and all the variables

-(+0.75x)*28x+7*28x+1))-(74)=0

We add all the numbers together, and all the variables

-(+0.75x)*28x+7*28x=0

We multiply parentheses

-0x^2+7*28x=0

Wy multiply elements

-0x^2+196x=0

We add all the numbers together, and all the variables

-1x^2+196x=0

a = -1; b = 196; c = 0;
Δ = b2-4ac
Δ = 1962-4·(-1)·0
Δ = 38416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{38416}=196$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(196)-196}{2*-1}=\frac{-392}{-2}
=+196
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(196)+196}{2*-1}=\frac{0}{-2}
=0
$