7n+4/7+2n2/7=-3

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Solution for 7n+4/7+2n2/7=-3 equation:



7n+4/7+2n^2/7=-3
We move all terms to the left:
7n+4/7+2n^2/7-(-3)=0
We add all the numbers together, and all the variables
2n^2/7+7n+3+4/7=0
We multiply all the terms by the denominator
2n^2+7n*7+4+3*7=0
We add all the numbers together, and all the variables
2n^2+7n*7+25=0
Wy multiply elements
2n^2+49n+25=0
a = 2; b = 49; c = +25;
Δ = b2-4ac
Δ = 492-4·2·25
Δ = 2201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-\sqrt{2201}}{2*2}=\frac{-49-\sqrt{2201}}{4} $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+\sqrt{2201}}{2*2}=\frac{-49+\sqrt{2201}}{4} $

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