-2(5+2v)=2(v+4)

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Solution for -2(5+2v)=2(v+4) equation: 



-2(5+2v)=2(v+4)

We move all terms to the left:

-2(5+2v)-(2(v+4))=0

We add all the numbers together, and all the variables

-2(2v+5)-(2(v+4))=0

We multiply parentheses

-4v-(2(v+4))-10=0



We calculate terms in parentheses: -(2(v+4)), so:

2(v+4)

We multiply parentheses

2v+8

Back to the equation:

-(2v+8)



We get rid of parentheses

-4v-2v-8-10=0

We add all the numbers together, and all the variables

-6v-18=0

We move all terms containing v to the left, all other terms to the right

-6v=18

v=18/-6

v=-3

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