38=3(2b-6)+4(b-6)

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Solution for 38=3(2b-6)+4(b-6) equation: 



38=3(2b-6)+4(b-6)

We move all terms to the left:

38-(3(2b-6)+4(b-6))=0



We calculate terms in parentheses: -(3(2b-6)+4(b-6)), so:

3(2b-6)+4(b-6)

We multiply parentheses

6b+4b-18-24

We add all the numbers together, and all the variables

10b-42

Back to the equation:

-(10b-42)



We get rid of parentheses

-10b+42+38=0

We add all the numbers together, and all the variables

-10b+80=0

We move all terms containing b to the left, all other terms to the right

-10b=-80

b=-80/-10

b=+8

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