11=4(n+5)-5(2n+3)

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Solution for 11=4(n+5)-5(2n+3) equation: 



11=4(n+5)-5(2n+3)

We move all terms to the left:

11-(4(n+5)-5(2n+3))=0



We calculate terms in parentheses: -(4(n+5)-5(2n+3)), so:

4(n+5)-5(2n+3)

We multiply parentheses

4n-10n+20-15

We add all the numbers together, and all the variables

-6n+5

Back to the equation:

-(-6n+5)



We get rid of parentheses

6n-5+11=0

We add all the numbers together, and all the variables

6n+6=0

We move all terms containing n to the left, all other terms to the right

6n=-6

n=-6/6

n=-1

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