3k-(4+k)=-(2k+4)

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Solution for 3k-(4+k)=-(2k+4) equation: 



3k-(4+k)=-(2k+4)

We move all terms to the left:

3k-(4+k)-(-(2k+4))=0

We add all the numbers together, and all the variables

3k-(k+4)-(-(2k+4))=0

We get rid of parentheses

3k-k-(-(2k+4))-4=0



We calculate terms in parentheses: -(-(2k+4)), so:

-(2k+4)

We get rid of parentheses

-2k-4

Back to the equation:

-(-2k-4)



We add all the numbers together, and all the variables

2k-(-2k-4)-4=0

We get rid of parentheses

2k+2k+4-4=0

We add all the numbers together, and all the variables

4k=0

k=0/4

k=0

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