1/4(20x+16)-14=1/3(18x-12)

Solution for 1/4(20x+16)-14=1/3(18x-12) equation:

1/4(20x+16)-14=1/3(18x-12)

We move all terms to the left:

1/4(20x+16)-14-(1/3(18x-12))=0


Domain of the equation: 4(20x+16)!=0

x∈R



Domain of the equation: 3(18x-12))!=0

x∈R


We calculate fractions


(3x1/(4(20x+16)*3(18x-12)))+(-4x2/(4(20x+16)*3(18x-12)))-14=0


We calculate terms in parentheses: +(3x1/(4(20x+16)*3(18x-12))), so:

3x1/(4(20x+16)*3(18x-12))

We multiply all the terms by the denominator


3x1

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)



We calculate terms in parentheses: +(-4x2/(4(20x+16)*3(18x-12))), so:

-4x2/(4(20x+16)*3(18x-12))

We multiply all the terms by the denominator


-4x2

We add all the numbers together, and all the variables

-4x^2

Back to the equation:

+(-4x^2)


We get rid of parentheses

-4x^2+3x-14=0

a = -4; b = 3; c = -14;
Δ = b2-4ac
Δ = 32-4·(-4)·(-14)
Δ = -215
Delta is less than zero, so there is no solution for the equation