7=8(10c+3)+2

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Solution for 7=8(10c+3)+2 equation: 



7=8(10c+3)+2

We move all terms to the left:

7-(8(10c+3)+2)=0



We calculate terms in parentheses: -(8(10c+3)+2), so:

8(10c+3)+2

We multiply parentheses

80c+24+2

We add all the numbers together, and all the variables

80c+26

Back to the equation:

-(80c+26)



We get rid of parentheses

-80c-26+7=0

We add all the numbers together, and all the variables

-80c-19=0

We move all terms containing c to the left, all other terms to the right

-80c=19

c=19/-80

c=-19/80

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