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(2x+5)+x+(3x-4=43
We move all terms to the left:
(2x+5)+x+(3x-4-(43)=0
We add all the numbers together, and all the variables
x+(2x+5)+(3x-4-43=0
We get rid of parentheses
x+2x+(3x-4-43+5=0
We add all the numbers together, and all the variables
3x+(3x-4-43+5=0
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