4(v-1)=8v+2-2(-4v-6)

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Solution for 4(v-1)=8v+2-2(-4v-6) equation: 



4(v-1)=8v+2-2(-4v-6)

We move all terms to the left:

4(v-1)-(8v+2-2(-4v-6))=0

We multiply parentheses

4v-(8v+2-2(-4v-6))-4=0



We calculate terms in parentheses: -(8v+2-2(-4v-6)), so:

8v+2-2(-4v-6)

determiningTheFunctionDomain
8v-2(-4v-6)+2

We multiply parentheses

8v+8v+12+2

We add all the numbers together, and all the variables

16v+14

Back to the equation:

-(16v+14)



We get rid of parentheses

4v-16v-14-4=0

We add all the numbers together, and all the variables

-12v-18=0

We move all terms containing v to the left, all other terms to the right

-12v=18

v=18/-12

v=-1+1/2

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