(2x+5)+x+(3x-4)=43

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Solution for (2x+5)+x+(3x-4)=43 equation: 



(2x+5)+x+(3x-4)=43

We move all terms to the left:

(2x+5)+x+(3x-4)-(43)=0

We add all the numbers together, and all the variables

x+(2x+5)+(3x-4)-43=0

We get rid of parentheses

x+2x+3x+5-4-43=0

We add all the numbers together, and all the variables

6x-42=0

We move all terms containing x to the left, all other terms to the right

6x=42

x=42/6

x=7

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