7/6x+5/12=2+5/18x

Solution for 7/6x+5/12=2+5/18x equation:

7/6x+5/12=2+5/18x

We move all terms to the left:

7/6x+5/12-(2+5/18x)=0


Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R



Domain of the equation: 18x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

7/6x-(5/18x+2)+5/12=0

We get rid of parentheses

7/6x-5/18x-2+5/12=0

We calculate fractions


540x^2/1296x^2+1512x/1296x^2+(-360x)/1296x^2-2=0

We multiply all the terms by the denominator


540x^2+1512x+(-360x)-2*1296x^2=0

Wy multiply elements

540x^2-2592x^2+1512x+(-360x)=0

We get rid of parentheses

540x^2-2592x^2+1512x-360x=0

We add all the numbers together, and all the variables

-2052x^2+1152x=0

a = -2052; b = 1152; c = 0;
Δ = b2-4ac
Δ = 11522-4·(-2052)·0
Δ = 1327104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1327104}=1152$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1152)-1152}{2*-2052}=\frac{-2304}{-4104}
=32/57
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1152)+1152}{2*-2052}=\frac{0}{-4104}
=0
$