7-2(7b-5)=-7(b+1)+b

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Solution for 7-2(7b-5)=-7(b+1)+b equation: 



7-2(7b-5)=-7(b+1)+b

We move all terms to the left:

7-2(7b-5)-(-7(b+1)+b)=0

We multiply parentheses

-14b-(-7(b+1)+b)+10+7=0



We calculate terms in parentheses: -(-7(b+1)+b), so:

-7(b+1)+b

We add all the numbers together, and all the variables

b-7(b+1)

We multiply parentheses

b-7b-7

We add all the numbers together, and all the variables

-6b-7

Back to the equation:

-(-6b-7)



We add all the numbers together, and all the variables

-14b-(-6b-7)+17=0

We get rid of parentheses

-14b+6b+7+17=0

We add all the numbers together, and all the variables

-8b+24=0

We move all terms containing b to the left, all other terms to the right

-8b=-24

b=-24/-8

b=+3

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