28+3(2k-4)=8(3k+2)-18

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Solution for 28+3(2k-4)=8(3k+2)-18 equation: 



28+3(2k-4)=8(3k+2)-18

We move all terms to the left:

28+3(2k-4)-(8(3k+2)-18)=0

We multiply parentheses

6k-(8(3k+2)-18)-12+28=0



We calculate terms in parentheses: -(8(3k+2)-18), so:

8(3k+2)-18

We multiply parentheses

24k+16-18

We add all the numbers together, and all the variables

24k-2

Back to the equation:

-(24k-2)



We add all the numbers together, and all the variables

6k-(24k-2)+16=0

We get rid of parentheses

6k-24k+2+16=0

We add all the numbers together, and all the variables

-18k+18=0

We move all terms containing k to the left, all other terms to the right

-18k=-18

k=-18/-18

k=1

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