6x-3(3-2x)=3(x-5)-39

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Solution for 6x-3(3-2x)=3(x-5)-39 equation: 



6x-3(3-2x)=3(x-5)-39

We move all terms to the left:

6x-3(3-2x)-(3(x-5)-39)=0

We add all the numbers together, and all the variables

6x-3(-2x+3)-(3(x-5)-39)=0

We multiply parentheses

6x+6x-(3(x-5)-39)-9=0



We calculate terms in parentheses: -(3(x-5)-39), so:

3(x-5)-39

We multiply parentheses

3x-15-39

We add all the numbers together, and all the variables

3x-54

Back to the equation:

-(3x-54)



We add all the numbers together, and all the variables

12x-(3x-54)-9=0

We get rid of parentheses

12x-3x+54-9=0

We add all the numbers together, and all the variables

9x+45=0

We move all terms containing x to the left, all other terms to the right

9x=-45

x=-45/9

x=-5

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