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x(x+1)=4160
We move all terms to the left:
x(x+1)-(4160)=0
We multiply parentheses
x^2+x-4160=0
a = 1; b = 1; c = -4160;
Δ = b2-4ac
Δ = 12-4·1·(-4160)
Δ = 16641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16641}=129$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-129}{2*1}=\frac{-130}{2} =-65 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+129}{2*1}=\frac{128}{2} =64 $
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