6n-(31n-18)=12(n+1)+3n

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Solution for 6n-(31n-18)=12(n+1)+3n equation: 



6n-(31n-18)=12(n+1)+3n

We move all terms to the left:

6n-(31n-18)-(12(n+1)+3n)=0

We get rid of parentheses

6n-31n-(12(n+1)+3n)+18=0



We calculate terms in parentheses: -(12(n+1)+3n), so:

12(n+1)+3n

We add all the numbers together, and all the variables

3n+12(n+1)

We multiply parentheses

3n+12n+12

We add all the numbers together, and all the variables

15n+12

Back to the equation:

-(15n+12)



We add all the numbers together, and all the variables

-25n-(15n+12)+18=0

We get rid of parentheses

-25n-15n-12+18=0

We add all the numbers together, and all the variables

-40n+6=0

We move all terms containing n to the left, all other terms to the right

-40n=-6

n=-6/-40

n=3/20

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