7-2(7b-5)=7(b+1)+b

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Solution for 7-2(7b-5)=7(b+1)+b equation: 



7-2(7b-5)=7(b+1)+b

We move all terms to the left:

7-2(7b-5)-(7(b+1)+b)=0

We multiply parentheses

-14b-(7(b+1)+b)+10+7=0



We calculate terms in parentheses: -(7(b+1)+b), so:

7(b+1)+b

We add all the numbers together, and all the variables

b+7(b+1)

We multiply parentheses

b+7b+7

We add all the numbers together, and all the variables

8b+7

Back to the equation:

-(8b+7)



We add all the numbers together, and all the variables

-14b-(8b+7)+17=0

We get rid of parentheses

-14b-8b-7+17=0

We add all the numbers together, and all the variables

-22b+10=0

We move all terms containing b to the left, all other terms to the right

-22b=-10

b=-10/-22

b=5/11

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