7-2(5-3y)=4(y-3)+5

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Solution for 7-2(5-3y)=4(y-3)+5 equation: 



7-2(5-3y)=4(y-3)+5

We move all terms to the left:

7-2(5-3y)-(4(y-3)+5)=0

We add all the numbers together, and all the variables

-2(-3y+5)-(4(y-3)+5)+7=0

We multiply parentheses

6y-(4(y-3)+5)-10+7=0



We calculate terms in parentheses: -(4(y-3)+5), so:

4(y-3)+5

We multiply parentheses

4y-12+5

We add all the numbers together, and all the variables

4y-7

Back to the equation:

-(4y-7)



We add all the numbers together, and all the variables

6y-(4y-7)-3=0

We get rid of parentheses

6y-4y+7-3=0

We add all the numbers together, and all the variables

2y+4=0

We move all terms containing y to the left, all other terms to the right

2y=-4

y=-4/2

y=-2

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