(3x+4)/5=(x-3)/2

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Solution for (3x+4)/5=(x-3)/2 equation: 



(3x+4)/5=(x-3)/2

We move all terms to the left:

(3x+4)/5-((x-3)/2)=0

We calculate fractions


3x/()+(-((x-3)*5)/()=0



We calculate terms in parentheses: +(-((x-3)*5)/(), so:

-((x-3)*5)/(

We multiply all the terms by the denominator


-((x-3)*5)



We calculate terms in parentheses: -((x-3)*5), so:

(x-3)*5

We multiply parentheses

5x-15

Back to the equation:

-(5x-15)



We get rid of parentheses

-5x+15

Back to the equation:

+(-5x+15)



We get rid of parentheses

3x/()-5x+15=0

We multiply all the terms by the denominator


3x-5x*()+15*()=0

We add all the numbers together, and all the variables

3x-5x*()=0

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