(y+2)(y+5)=(2y-1)(y-6

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Solution for (y+2)(y+5)=(2y-1)(y-6 equation: 



(y+2)(y+5)=(2y-1)(y-6

We move all terms to the left:

(y+2)(y+5)-((2y-1)(y-6)=0

We multiply parentheses ..

(+y^2+5y+2y+10)-((2y-1)(y-6)=0



We calculate terms in parentheses: -((2y-1)(y-6), so:

(2y-1)(y-6



We get rid of parentheses

y^2+5y+2y-((2y-1)(y-6)+10=0

We multiply parentheses ..

y^2-((+2y^2-12y-1y+6)+10+5y+2y=0

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