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9(11-k)=3(3k-5)
We move all terms to the left:
9(11-k)-(3(3k-5))=0
We add all the numbers together, and all the variables
9(-1k+11)-(3(3k-5))=0
We multiply parentheses
-9k-(3(3k-5))+99=0
We calculate terms in parentheses: -(3(3k-5)), so:We get rid of parentheses
3(3k-5)
We multiply parentheses
9k-15
Back to the equation:
-(9k-15)
-9k-9k+15+99=0
We add all the numbers together, and all the variables
-18k+114=0
We move all terms containing k to the left, all other terms to the right
-18k=-114
k=-114/-18
k=6+1/3
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