7(z+3)=4z-6

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Solution for 7(z+3)=4z-6 equation: 



7(z+3)=4z-6

We move all terms to the left:

7(z+3)-(4z-6)=0

We multiply parentheses

7z-(4z-6)+21=0

We get rid of parentheses

7z-4z+6+21=0

We add all the numbers together, and all the variables

3z+27=0

We move all terms containing z to the left, all other terms to the right

3z=-27

z=-27/3

z=-9

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