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(x+1)(x+6)=23+12.56
We move all terms to the left:
(x+1)(x+6)-(23+12.56)=0
We add all the numbers together, and all the variables
(x+1)(x+6)-(35.56)=0
We add all the numbers together, and all the variables
(x+1)(x+6)-35.56=0
We multiply parentheses ..
(+x^2+6x+x+6)-35.56=0
We get rid of parentheses
x^2+6x+x+6-35.56=0
We add all the numbers together, and all the variables
x^2+7x-29.56=0
a = 1; b = 7; c = -29.56;
Δ = b2-4ac
Δ = 72-4·1·(-29.56)
Δ = 167.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{167.24}}{2*1}=\frac{-7-\sqrt{167.24}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{167.24}}{2*1}=\frac{-7+\sqrt{167.24}}{2} $
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