7(4a+5)-5a=5(3a-1)

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Solution for 7(4a+5)-5a=5(3a-1) equation:



7(4a+5)-5a=5(3a-1)
We move all terms to the left:
7(4a+5)-5a-(5(3a-1))=0
We add all the numbers together, and all the variables
-5a+7(4a+5)-(5(3a-1))=0
We multiply parentheses
-5a+28a-(5(3a-1))+35=0
We calculate terms in parentheses: -(5(3a-1)), so:
5(3a-1)
We multiply parentheses
15a-5
Back to the equation:
-(15a-5)
We add all the numbers together, and all the variables
23a-(15a-5)+35=0
We get rid of parentheses
23a-15a+5+35=0
We add all the numbers together, and all the variables
8a+40=0
We move all terms containing a to the left, all other terms to the right
8a=-40
a=-40/8
a=-5

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