9x+3*(32-3x)/2=93

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Solution for 9x+3*(32-3x)/2=93 equation: 



9x+3(32-3x)/2=93

We move all terms to the left:

9x+3(32-3x)/2-(93)=0

We add all the numbers together, and all the variables

9x+3(-3x+32)/2-93=0

We multiply all the terms by the denominator


9x*2+3(-3x+32)-93*2=0

We add all the numbers together, and all the variables

9x*2+3(-3x+32)-186=0

We multiply parentheses

9x*2-9x+96-186=0

Wy multiply elements

18x-9x+96-186=0

We add all the numbers together, and all the variables

9x-90=0

We move all terms containing x to the left, all other terms to the right

9x=90

x=90/9

x=10

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