4x+10-(5x2)=40

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Solution for 4x+10-(5x2)=40 equation: 



4x+10-(5x^2)=40

We move all terms to the left:

4x+10-(5x^2)-(40)=0

determiningTheFunctionDomain
-5x^2+4x+10-40=0

We add all the numbers together, and all the variables

-5x^2+4x-30=0

a = -5; b = 4; c = -30;
Δ = b2-4ac
Δ = 42-4·(-5)·(-30)
Δ = -584
Delta is less than zero, so there is no solution for the equation

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