7(z+2)-2=7z+12

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Solution for 7(z+2)-2=7z+12 equation: 



7(z+2)-2=7z+12

We move all terms to the left:

7(z+2)-2-(7z+12)=0

We multiply parentheses

7z-(7z+12)+14-2=0

We get rid of parentheses

7z-7z-12+14-2=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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