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(4x-20)+(x+12)+(x-1)=59
We move all terms to the left:
(4x-20)+(x+12)+(x-1)-(59)=0
We get rid of parentheses
4x+x+x-20+12-1-59=0
We add all the numbers together, and all the variables
6x-68=0
We move all terms containing x to the left, all other terms to the right
6x=68
x=68/6
x=11+1/3
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