(2x+1)+(3x+2)=(3x+9)

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Solution for (2x+1)+(3x+2)=(3x+9) equation: 



(2x+1)+(3x+2)=(3x+9)

We move all terms to the left:

(2x+1)+(3x+2)-((3x+9))=0

We get rid of parentheses

2x+3x-((3x+9))+1+2=0



We calculate terms in parentheses: -((3x+9)), so:

(3x+9)

We get rid of parentheses

3x+9

Back to the equation:

-(3x+9)



We add all the numbers together, and all the variables

5x-(3x+9)+3=0

We get rid of parentheses

5x-3x-9+3=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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