17(t+2)=4(t-10)-30

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Solution for 17(t+2)=4(t-10)-30 equation: 



17(t+2)=4(t-10)-30

We move all terms to the left:

17(t+2)-(4(t-10)-30)=0

We multiply parentheses

17t-(4(t-10)-30)+34=0



We calculate terms in parentheses: -(4(t-10)-30), so:

4(t-10)-30

We multiply parentheses

4t-40-30

We add all the numbers together, and all the variables

4t-70

Back to the equation:

-(4t-70)



We get rid of parentheses

17t-4t+70+34=0

We add all the numbers together, and all the variables

13t+104=0

We move all terms containing t to the left, all other terms to the right

13t=-104

t=-104/13

t=-8

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