7(y-3)+5=4(2-y)+3

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Solution for 7(y-3)+5=4(2-y)+3 equation: 



7(y-3)+5=4(2-y)+3

We move all terms to the left:

7(y-3)+5-(4(2-y)+3)=0

We add all the numbers together, and all the variables

7(y-3)-(4(-1y+2)+3)+5=0

We multiply parentheses

7y-(4(-1y+2)+3)-21+5=0



We calculate terms in parentheses: -(4(-1y+2)+3), so:

4(-1y+2)+3

We multiply parentheses

-4y+8+3

We add all the numbers together, and all the variables

-4y+11

Back to the equation:

-(-4y+11)



We add all the numbers together, and all the variables

7y-(-4y+11)-16=0

We get rid of parentheses

7y+4y-11-16=0

We add all the numbers together, and all the variables

11y-27=0

We move all terms containing y to the left, all other terms to the right

11y=27

y=27/11

y=2+5/11

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