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4(x-3)=3(4+x)*
We move all terms to the left:
4(x-3)-(3(4+x)*)=0
We add all the numbers together, and all the variables
4(x-3)-(3(x+4)*)=0
We multiply parentheses
4x-(3(x+4)*)-12=0
We calculate terms in parentheses: -(3(x+4)*), so:We get rid of parentheses
3(x+4)*
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
4x-3x-12-12=0
We add all the numbers together, and all the variables
x-24=0
We move all terms containing x to the left, all other terms to the right
x=24
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