-4(-4y+1)-y=3(y-3)-3

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Solution for -4(-4y+1)-y=3(y-3)-3 equation: 



-4(-4y+1)-y=3(y-3)-3

We move all terms to the left:

-4(-4y+1)-y-(3(y-3)-3)=0

We add all the numbers together, and all the variables

-1y-4(-4y+1)-(3(y-3)-3)=0

We multiply parentheses

-1y+16y-(3(y-3)-3)-4=0



We calculate terms in parentheses: -(3(y-3)-3), so:

3(y-3)-3

We multiply parentheses

3y-9-3

We add all the numbers together, and all the variables

3y-12

Back to the equation:

-(3y-12)



We add all the numbers together, and all the variables

15y-(3y-12)-4=0

We get rid of parentheses

15y-3y+12-4=0

We add all the numbers together, and all the variables

12y+8=0

We move all terms containing y to the left, all other terms to the right

12y=-8

y=-8/12

y=-2/3

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