7(x-3)/8=8(x+2)/3

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Solution for 7(x-3)/8=8(x+2)/3 equation: 



7(x-3)/8=8(x+2)/3

We move all terms to the left:

7(x-3)/8-(8(x+2)/3)=0

We calculate fractions


7x/()+(-(8(x+2)*8)/()=0



We calculate terms in parentheses: +(-(8(x+2)*8)/(), so:

-(8(x+2)*8)/(

We multiply all the terms by the denominator


-(8(x+2)*8)



We calculate terms in parentheses: -(8(x+2)*8), so:

8(x+2)*8

We multiply parentheses

64x+128

Back to the equation:

-(64x+128)



We get rid of parentheses

-64x-128

Back to the equation:

+(-64x-128)



We get rid of parentheses

7x/()-64x-128=0

We multiply all the terms by the denominator


7x-64x*()-128*()=0

We add all the numbers together, and all the variables

7x-64x*()=0

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