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x2+30x=-200
We move all terms to the left:
x2+30x-(-200)=0
We add all the numbers together, and all the variables
x^2+30x+200=0
a = 1; b = 30; c = +200;
Δ = b2-4ac
Δ = 302-4·1·200
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-10}{2*1}=\frac{-40}{2} =-20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+10}{2*1}=\frac{-20}{2} =-10 $
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