6(4x-4)-4(2x-11)=3(5x+1)-2

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Solution for 6(4x-4)-4(2x-11)=3(5x+1)-2 equation:



6(4x-4)-4(2x-11)=3(5x+1)-2
We move all terms to the left:
6(4x-4)-4(2x-11)-(3(5x+1)-2)=0
We multiply parentheses
24x-8x-(3(5x+1)-2)-24+44=0
We calculate terms in parentheses: -(3(5x+1)-2), so:
3(5x+1)-2
We multiply parentheses
15x+3-2
We add all the numbers together, and all the variables
15x+1
Back to the equation:
-(15x+1)
We add all the numbers together, and all the variables
16x-(15x+1)+20=0
We get rid of parentheses
16x-15x-1+20=0
We add all the numbers together, and all the variables
x+19=0
We move all terms containing x to the left, all other terms to the right
x=-19

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