19(2x-1)+11=15x-5(2-3x)

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Solution for 19(2x-1)+11=15x-5(2-3x) equation:



19(2x-1)+11=15x-5(2-3x)
We move all terms to the left:
19(2x-1)+11-(15x-5(2-3x))=0
We add all the numbers together, and all the variables
19(2x-1)-(15x-5(-3x+2))+11=0
We multiply parentheses
38x-(15x-5(-3x+2))-19+11=0
We calculate terms in parentheses: -(15x-5(-3x+2)), so:
15x-5(-3x+2)
We multiply parentheses
15x+15x-10
We add all the numbers together, and all the variables
30x-10
Back to the equation:
-(30x-10)
We add all the numbers together, and all the variables
38x-(30x-10)-8=0
We get rid of parentheses
38x-30x+10-8=0
We add all the numbers together, and all the variables
8x+2=0
We move all terms containing x to the left, all other terms to the right
8x=-2
x=-2/8
x=-1/4

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