7(v+3)=-2(9v-9)+7v

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Solution for 7(v+3)=-2(9v-9)+7v equation: 



7(v+3)=-2(9v-9)+7v

We move all terms to the left:

7(v+3)-(-2(9v-9)+7v)=0

We multiply parentheses

7v-(-2(9v-9)+7v)+21=0



We calculate terms in parentheses: -(-2(9v-9)+7v), so:

-2(9v-9)+7v

We add all the numbers together, and all the variables

7v-2(9v-9)

We multiply parentheses

7v-18v+18

We add all the numbers together, and all the variables

-11v+18

Back to the equation:

-(-11v+18)



We get rid of parentheses

7v+11v-18+21=0

We add all the numbers together, and all the variables

18v+3=0

We move all terms containing v to the left, all other terms to the right

18v=-3

v=-3/18

v=-1/6

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