2/3(6d+3)+(d-8)=-4+12

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Solution for 2/3(6d+3)+(d-8)=-4+12 equation: 



2/3(6d+3)+(d-8)=-4+12

We move all terms to the left:

2/3(6d+3)+(d-8)-(-4+12)=0



Domain of the equation: 3(6d+3)!=0

d∈R



We add all the numbers together, and all the variables

2/3(6d+3)+(d-8)-8=0

We get rid of parentheses

2/3(6d+3)+d-8-8=0

We multiply all the terms by the denominator


d*3(6d+3)-8*3(6d+3)-8*3(6d+3)+2=0

Wy multiply elements

3d^2(6-24d(6-24d(6+2=0

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